Q1. The voltage across a discharging capacitor is
Using Matlab generate a table of voltage v(t) versus time t, for t = 0 to 50 seconds with increment of 5 s.
function []=q1()
t=0:5:50
v=10*(1-exp(-0.2*t))
end
Q2. Use Matlab to evaluate a complex number
function []=q2()
z1= [(3+6*j)*(6+j*4)]/[(2+1*j)*(2*j)]
z=z1+7+10*j
end
Q3. Write a function-file in Matlab that can be used to calculate the equivalent resistance of 4 parallel connected resistors. Take the resistances values as 1ohm, 2ohm, 3ohm, 4ohm.
function [req]=q3(r1,r2,r3,r4)
a = (1/r1)+ (1/r2) + (1/r3) + (1/r4);
req = 1/a;
end
Q4. Use Matlab to simplify the expression
function []=q4()
a = 0.5 + 6*j + 3.5*exp(0.6*j) + (3+6*j)*exp(0.3*pi)
end
Q5. The voltage v and current I of a certain diode are related by the expression i= Isexp[v/(nVT)]. If Is= 1.0 X 10-14A, n=2 & VT= 26mV, Plot the current versus voltage curve of the diode for diode voltage between 0 to 0.6V.
function []=q5()
IS = 1*[10^(-14)]
n=2
VT= .026
v = 0:.01:.6
i= IS*(exp(v/(n*VT)))
plot(v,i)
xlabel('Volgate in volts')
ylabel('Current in mA')
title('V-I Characteristic of Forward Bias Diode')
end
Q6. The current flowing through a drain of a field effect transistor during saturation is given as IDS = k(VGS-Vt)^2. If Vt= 1V, k= 2.5 mA/V2. Plot IDS for VGS: 1.5, 2,2.5………5V
function []=q6()
Vt = 1
k= 2.5
VGS = 1.5:.5:5
IDS = k*((VGS - Vt).^2)
plot(VGS,IDS)
xlabel('Volgate in volts')
ylabel('Current in A')
title('V-I Characteristic of FET')
end
Q7. Plot the voltage across a parallel RLC circuit given as v1(t)= 5e^(2t)sin(10πt) & v2(t)= 5e^(2t)cos(10πt) in same graph.
function []=q7()
t=0:.01:1;
a= 5*(exp(2*t))
v1= a.*(sin(10*pi*t));
v2 = a.*(cos(10*pi*t));
plot(t,v1,'*',t,v2,'o');
xlabel('Volgate in volts')
ylabel('Current in A')
title('RLC Circuit')
end
Q8. Obtain the polar plot of z= r^(-n)e^(jnθ) for r = 1.2, θ=15 degree & n=1 to 20.
function []=q8()
r = 1.2
theta = (15*pi)/180;
n = 1:20;
z = (r.^(-n)).*(exp(n.*theta*j));
polar(n,z);
title('Polar Plot')
end
Q9. A message signal m(t) and the carrier signal c(t) of a communication system are, respectively: m(t) = 4cos(1200πt). A double-sideband suppressed carrier s(t) is given as s(t) = m(t)c(t). Plot m(t), c(t) & s(t) using subplot.
function []=q9()
t = 0:.0000001:.01;
c = 10*cos(10000*pi*t);
m = 4*cos(1200*pi*t);
s = m.*c;
subplot(3,1,1)
plot(t,c)
title('Carrier Signal')
subplot(3,1,2)
plot(t,m)
title('Message Signal')
subplot(3,1,3)
plot(t,s)
title('DSB-SC Modulated Signal')
end
Q10. Write a MATLAB program to add all the even numbers from 0 to 100.
function [sum]=q10()
sum = 0;
for n= 0:2:100
sum = sum + n;
end
end
Q11. Add all the terms in the series
until the sum exceeds 1.995. Print out the sum and the number of terms needed to just exceed the sum of 1.995.
function []=q11()
sum=0;
for n = 0:10000
sum = sum + 1/(2^n);
if(sum>1.995)
break;
end
end
sum
n
end
Q12. The Fibonacci sequence is given as 1 1 2 3 5 8 13 21 34 ….. Write a MATLAB program to generate the Fibonacci sequence up to the twelfth term. Print out the results.
function []=q12(n)
a(1)=1
a(2)=1
for i=3:n
a(i)= a(i-1)+a(i-2);
end
a
end
Q13. Write a function-file to obtain the dot product and the vector product of two vectors a & b. Use the function to evaluate the dot and vector products of vectors x and y, where x = (1 5 6) & y = (2 3 8).
function []=q13()
a = [1 5 6];
b= [2 3 8];
dot= a.*b
cross(1)= a(2)*b(3)- b(2)*a(3);
cross(2)= -(a(1)*b(3)-b(1)*a(3));
cross(3)= b(2)*a(1)- b(1)*a(2);
cross
end
function []=q1()
t=0:5:50
v=10*(1-exp(-0.2*t))
end
Q2. Use Matlab to evaluate a complex number
z1= [(3+6*j)*(6+j*4)]/[(2+1*j)*(2*j)]
z=z1+7+10*j
end
Q3. Write a function-file in Matlab that can be used to calculate the equivalent resistance of 4 parallel connected resistors. Take the resistances values as 1ohm, 2ohm, 3ohm, 4ohm.
function [req]=q3(r1,r2,r3,r4)
a = (1/r1)+ (1/r2) + (1/r3) + (1/r4);
req = 1/a;
end
Q4. Use Matlab to simplify the expression
a = 0.5 + 6*j + 3.5*exp(0.6*j) + (3+6*j)*exp(0.3*pi)
end
Q5. The voltage v and current I of a certain diode are related by the expression i= Isexp[v/(nVT)]. If Is= 1.0 X 10-14A, n=2 & VT= 26mV, Plot the current versus voltage curve of the diode for diode voltage between 0 to 0.6V.
function []=q5()
IS = 1*[10^(-14)]
n=2
VT= .026
v = 0:.01:.6
i= IS*(exp(v/(n*VT)))
plot(v,i)
xlabel('Volgate in volts')
ylabel('Current in mA')
title('V-I Characteristic of Forward Bias Diode')
end
Q6. The current flowing through a drain of a field effect transistor during saturation is given as IDS = k(VGS-Vt)^2. If Vt= 1V, k= 2.5 mA/V2. Plot IDS for VGS: 1.5, 2,2.5………5V
function []=q6()
Vt = 1
k= 2.5
VGS = 1.5:.5:5
IDS = k*((VGS - Vt).^2)
plot(VGS,IDS)
xlabel('Volgate in volts')
ylabel('Current in A')
title('V-I Characteristic of FET')
end
Q7. Plot the voltage across a parallel RLC circuit given as v1(t)= 5e^(2t)sin(10πt) & v2(t)= 5e^(2t)cos(10πt) in same graph.
function []=q7()
t=0:.01:1;
a= 5*(exp(2*t))
v1= a.*(sin(10*pi*t));
v2 = a.*(cos(10*pi*t));
plot(t,v1,'*',t,v2,'o');
xlabel('Volgate in volts')
ylabel('Current in A')
title('RLC Circuit')
end
Q8. Obtain the polar plot of z= r^(-n)e^(jnθ) for r = 1.2, θ=15 degree & n=1 to 20.
function []=q8()
r = 1.2
theta = (15*pi)/180;
n = 1:20;
z = (r.^(-n)).*(exp(n.*theta*j));
polar(n,z);
title('Polar Plot')
end
Q9. A message signal m(t) and the carrier signal c(t) of a communication system are, respectively: m(t) = 4cos(1200πt). A double-sideband suppressed carrier s(t) is given as s(t) = m(t)c(t). Plot m(t), c(t) & s(t) using subplot.
function []=q9()
t = 0:.0000001:.01;
c = 10*cos(10000*pi*t);
m = 4*cos(1200*pi*t);
s = m.*c;
subplot(3,1,1)
plot(t,c)
title('Carrier Signal')
subplot(3,1,2)
plot(t,m)
title('Message Signal')
subplot(3,1,3)
plot(t,s)
title('DSB-SC Modulated Signal')
end
Q10. Write a MATLAB program to add all the even numbers from 0 to 100.
function [sum]=q10()
sum = 0;
for n= 0:2:100
sum = sum + n;
end
end
Q11. Add all the terms in the series
function []=q11()
sum=0;
for n = 0:10000
sum = sum + 1/(2^n);
if(sum>1.995)
break;
end
end
sum
n
end
Q12. The Fibonacci sequence is given as 1 1 2 3 5 8 13 21 34 ….. Write a MATLAB program to generate the Fibonacci sequence up to the twelfth term. Print out the results.
function []=q12(n)
a(1)=1
a(2)=1
for i=3:n
a(i)= a(i-1)+a(i-2);
end
a
end
Q13. Write a function-file to obtain the dot product and the vector product of two vectors a & b. Use the function to evaluate the dot and vector products of vectors x and y, where x = (1 5 6) & y = (2 3 8).
function []=q13()
a = [1 5 6];
b= [2 3 8];
dot= a.*b
cross(1)= a(2)*b(3)- b(2)*a(3);
cross(2)= -(a(1)*b(3)-b(1)*a(3));
cross(3)= b(2)*a(1)- b(1)*a(2);
cross
end